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by rain1
1165 days ago
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we do, it's called the algebraic numbers! every polynomial with algebraic coefficients has 'n' solutions (counted with multiplicity)! so e.g. x^121 + sqrt(7)x^9 + fithroot(22)x^7 + (1+i)x^3 + 22/7 = 0 has 121 solutions. and they're all algebraic numbers: nothing weird like pi in there. |
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It's a stupid question, but it's not related to your response.