|
|
|
|
|
by LegionMammal978
1174 days ago
|
|
C has both translation-time UB and runtime UB. (C++ explicitly separates the two concepts into "ill-defined, no diagnostic required" and "undefined behavior".) You can tell them apart from the condition for UB to occur: if it's a translation-time condition, then it's translation-time UB, and if it's a runtime condition, then it's runtime UB. (Same with implicit UB: is it a translation-time or a runtime assumption being violated?) Usually when we talk about UB, we're implicitly talking about runtime UB, since translation-time UB is generally far less subtle. If a program contains only conditional runtime UB, the compiler is not permitted to break the entire program from the very beginning, since all possible executions that do not trigger runtime UB must execute correctly as per 5.1.2.3. |
|
I hadn't considered the C++ standard here, but 1.9 is much more clear than corresponding C verbiage. 1.9.5 is exactly what's described upthread, where any "execution [that] contains an undefined operation" has no prescribed behavior. But the note to the requirement immediately before that (1.9.4) doesn't use that language and instead "imposes no requirements on programs that contain UB". If they had intended only to avoid specifying semantics for programs that hit UB during some possible execution, they would have used the same language as 1.9.5.