[auno]

> Java isn't generic over exceptions. You can't write a method that takes an instance of Foo and says "my method throws whatever Foo.bar() throws"

If you bend over far enough backwards, and squint a bit, you can kind of do that...

    interface Runner<E extends Throwable> {
      public void run() throws E;
    }

    class Test {
      public static <E extends Throwable, T extends Runner<E>> void test(T runner) throws E {
        runner.run();
      }
    }

It compiles. I haven't tried running it though.