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by tomrod 1223 days ago
The representation by SVD would work almost identically. SVD is one of those absolutely magical, amazing algorithms that power a ton of things we do every day.
1 comments
wiredfool 1223 days ago
Especially if YCbCr is a linear transform of the RGB. (I'm not sure if it is, but it's likely to be close). If it is, it's essentially just making eigenvectors from a matrix with a different set of bases.
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bob1029 1223 days ago
> is a linear transform of the RGB

It is for every implementation I've seen. I have it defined both ways as 4x4 matrices in my code (3x3 is not in System.Numerics).

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planede 1222 days ago
It appears to be a linear transform from "gamma-adjusted" RGB. So probably not straight from sRGB. [1]

The article does not mention it, but I assume it just takes sRGB color components.

[1] https://en.wikipedia.org/wiki/YCbCr#R'G'B'_to_Y'PbPr

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