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by joshAg
1234 days ago
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The range is of values, not their representation in bits, which can be mapped in any order. You could specify that the bit representation for 0 was 0x1234 and the bit representation for 1 was 0x1134 and proceeded accordingly and the range of values for those 16 bits could still independently be [-32768, 32767] or [0, 65535] or [65536, 131071] if you wanted. We know the signed int they're talking about can't be the standard 1's complement because its stated range of values is [-32768, 32767]. If the representation were 1's complement the range would be [-32767, 32767] to accommodate the -0. It could be some modified form of 1's complement where they redefine the -0 to actually be -32768, but that's not 1's complement anymore. |
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