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by jdwg
1246 days ago
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Cycles on (X, A) really can connect parts of A to other parts that look remote if you are forced to stay within A. This is visible in the long exact sequence; when the third map is nonzero, you have cycles in A that become boundaries when you allow chains in X. Sorry, I do not see what you mean by "dual space," and I do not myself view chains as a analogous to functions. |
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(never mind the function analogy, I was trying to handwave a quotient in the other direction but that would fall immediately out of the direct sum if I understand correctly: A β (AβB)/B and B β (AβB)/A?)
* which forms a MΓΆbius band in its own way, because at H(A,β ) we feed it into πΌ as β β Cycles(A) but get it out of πΎ as Cycles(A) β β , leading to a "twist"?
[Edit: are you aware of Dan Piponi's blogging?
http://blog.sigfpe.com/2006/08/algebraic-topology-in-haskell...
http://blog.sigfpe.com/2006/08/what-can-we-measure-part-i.ht...
http://blog.sigfpe.com/2010/01/target-enumeration-with-euler...
etc.]