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by mark254 1257 days ago
Wouldn't a (3-D) cube have eight corners?

And 3 length dimensions plus time gives a hypercube, with 16 corners.

For 11 dimensions, 2048 corners... for 26, 2^26 ;)

2 comments

Good discussion on this at https://old.reddit.com/r/askmath/comments/10a2xmc/do_corners...

One of the requirements is that you have to clearly define whether your n-dimensional object is a solid.

You should instead try some belly-button logic.