lisp -> 1-n; s-expression 1st element ins () is the "memory index"
structs -> n * M; "m-expression" 1st element outside of () is the "memory index".
cons struc vs. cons lisp () is apples/oranages comparison.
if convert both the 'cons struc' and the cons lisp () to same byte vector/stack or equivalent byte tree/heap, then yes, both 'cons' functions are equivalent.
higher order equivalent of mealy state machine vs. moore state machine. [1]
side note:
( 1 - n ) vs (n * m) is context reference to ploting base 2 log(x).
lisp approach to dectorators / generators disucssion. https://stackoverflow.com/questions/32956033/is-there-a-stra...