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by metageek 5279 days ago
Even if you're not putting the RString struct on the stack, the embedded string optimization means calling malloc() just once instead of twice.
1 comments

You can allocate the string with one malloc:

    RString *s = malloc(sizeof(RString) + length); /* allocate 'length' bytes extra memory past the end of 's' */
    s->data = s + 1; /* to the extra memory past the start of the string struct */
Ruby strings are mutable, so you need to be able to free s->data without freeing the RString itself.

    s = realloc(s, sizeof(RString));
MRI objects are not relocatable so that won't work if realloc has to move the structure in memory
Nitpick: sizeof(RString) + length may overflow size_t.