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by yshklarov 1276 days ago
That is roughly correct. For a curve with smooth parametrization f(t) = (x(t), y(t)), with f'(t) ≠ 0 for all t, the curvature at the point f(t) is defined to be κ := |(f'(t)/|f'(t)|)'| -- the magnitude of the first derivative of the unit tangent vector. This is a nonnegative quantity, and is well defined, that is, independent of the specific parametrization of the curve (as legosexmagic said, you need to do something like this to get a quantity independent of the parametrization, but it is essentially a "normalized" second derivative).

The curvature comb consists (it seems to me) of a normal line segment at each point, whose length is directly proportional to the curvature there.

1 comments

Oops, my mistake: that is not the definition of curvature! The outer derivative must be taken with respect to arclength, rather than with respect to t.