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by int_19h
1304 days ago
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Function pointer types are a Turbo Pascal extension; in standard (Wirth/ISO) Pascal, you cannot have "type = function" etc, you can only use that syntax to declare arguments of function type. So they're not first-class values. They're closures because they capture the enclosing environment (variables). In your second example, what you're doing is the equivalent of reinterpret_cast between two incompatible pointer types (if they were compatible, you could have just assigned @sub to a variable of type MyFuncHidden). You cannot safely assume that your new signature faithfully corresponds to what the compiler does under the hood - that's an implementation detail. Furthermore, in this case, your function doesn't even try to access variables from the outer scope, and this would break if it did. |
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