[im-a-baby]

Yea, the issue is that nil's in Go are typed. So `err == nil` is checking err against error's nil value, but the value stored in err is *MyError's nil value.

    package main
    
    import "fmt"
    
    type MyError struct{}
    
    func (m *MyError) Error() string {
        return ""
    }
    
    func main() {
        var err error = nil
        var myErr *MyError = nil

        fmt.Println(err == myErr) // this is false
    }

[gregwebs]

Comparing different types normally is a type error. But for interfaces the non-interface value will be converted to the type of the interface value. This conversion gives it a boxed dynamic type. This is different type than just assigning nil, which is the untyped nil, which sets the interface to its zero value.

Normally one would not compare two interface values, so this issue really comes up when comparing an interface to nil. If Go had proper option types then this issue would go away.

https://go101.org/article/nil.html

package main

import "fmt"

type Err1 struct{}

func (m Err1) Error() string { return "" }

type Err2 struct{}

func (m Err2) Error() string { return "" }

func main() {

  var err error = nil

  var myErr1 *Err1 = nil

  var myErr2 *Err2 = nil

  fmt.Println(err == myErr1)                      // this is false
  fmt.Println(err == myErr2)                      // this is false
  fmt.Println((error)(myErr1) == (error)(myErr2)) // this is false. requires the cast to do the comparison
 }