[paxys]

Disagree with "across the board". Tech still has a lot of difficult problems and a crazy amount of money to be made, so premium talent will continue to command premium salaries. It's just that a "staff engineer" 4 years out of college won't be able to sleep their way into $500K in salary + stock.

[adam_arthur]

Comp is dictated by labor market dynamics, not by profitability of the product.

If you have 10 engineers of roughly equal skill competing for the same role, the company has more leverage to offer lower comp than if there’s just 1, or less than one.

Profitability just sets a cap on what can be paid.

That being said, I do agree that the best of the best will likely be able to maintain mid 6 figure comps. But it won’t be the norm as it has been.

There’s also theory vs practice. In practice very few companies have a high level of confidence about being able to quantify how much one engineer is worth vs another. Which is why 10x engineers can’t capture significantly higher comp than the median, even in the current (recent) market

[steviesands]

Does this logic work for lawyers? "Biglaw" firms are similar to FAANG in that it is a handful of companies that offer very high comp (235k for first year). There is a deluge of folks that apply from all universities to biglaw but generally they primarily hire from top tier law schools and even then not all make it.

Similar for Big 3 consulting firms (BCG, Bain, McKinsey) in that there is a huge application pool for positions but they are difficult to get and provide high pay.

[adam_arthur]

Yeah, for sure.

But in those cases the number of jobs is much more limited than was the case in tech in recent years.

Finance is a similar example. Bankers get paid a lot, but the number of them has been pretty static.

[steviesands]

Interestingly revenue per employee (1.2 - 1.8 mil per employee) at biglaw companies is similar to FAANG although i'd guess biglaw margins are higher as you have less other costs (infra).

https://www.law.com/law-firm-profile/?id=178&name=Latham-%26...