[dataflow]

The ">>>" operator works, the ">>" operator doesn't. The reason the former works is that it basically performs unsigned division by a power of 2; the latter does it signed. There's no floating-point.

[erikpukinskis]

What do the five >s and the , mean in this comment?

[dataflow]

>>> is bitwise right shift (fills in with zeros), >> is arithmetic right shift (fills in with the sign bit).

[a1369209993]

> >>> is bitwise right shift

Well, they're both bitwise right shifts, the ">>>" is specifically a logical or unsigned right shift.

[dataflow]

Whoops yes I meant logical.