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by ElectricalUnion 1334 days ago
> await result1;

> await result2;

> await result3;

Not really, you only have *1* request in flight.

And you're waiting for them sequentially.

You need asyncio.gather ( https://docs.python.org/3/library/asyncio-task.html#asyncio.... ) if you want to run tasks concurrently.

results = await asyncio.gather(result1, result2, result3)
1 comments
samsquire 1334 days ago
Before the first await result1 the coroutine objects are in flight.
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Spivak 1332 days ago
Nope, creating the coroutines doesn’t schedule them for execution. That only happens on await. Python is not eager. If you want that behavior you need to use create_task. It doesn’t work like spawning a thread and waiting on them.

From the docs: https://docs.python.org/3/library/asyncio-task.html

> Note that simply calling a coroutine will not schedule it to be executed:

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samsquire 1331 days ago
Oh this is not what I expected.

I think on C# you can await threads which is similar to a join() with a return value.

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