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by dragonwriter
1358 days ago
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> That's also currying right? No, currying is the transformation that takes a function f such that f(x0, x1, ... xn) = r and returns a function f' such that f'(x0)(x1)... (xn) = r. Haskell doesn’t really have currying so much as having only one argument functions and a syntax for defining them that means one way to define a function that works like the result of currying a multiargument function looks a lot like defining a multiargument function in other languages. |
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