|
|
|
|
|
by AdmiralAsshat
1357 days ago
|
|
Maybe I'm misunderstanding the note. Does this mean that the bash source code (written in C, I assume) now uses its own `malloc` function instead of what is provided by the standard C library? Or is it saying that `malloc` is a command I can call in bash? I assumed the latter, and couldn't figure out why I would need to manually allocate memory in a shell script. |
|
The idea is that you don’t need C libraries to run/compile bash.