Hacker News new | ask | show | jobs
by tomachello 1419 days ago
They just need one prisoner to guess correctly - then they all win. Regarding the base case scenario - if each prisoner guesses randomly, each has a 1/100 chance of guessing correctly, and hence they have an expected number of exactly one correct guess. So no deterministic approach can give 2 correct guesses, since no prisoner actually has any real information about their number.