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by veber-alex
1422 days ago
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> let b:&str = &"str"; This has nothing to do with DST but with type coercion. The type of `b` is `&&str` but you requested the type to be `&str` which is fine as the compiler can coerce from `&&str` to `&str` in this case. In the same way you can write let b: &i32 = &&&&1;
and it will compile fine |
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