[IHLayman]

Haskell coders have to do this often enough that there is a token that does this grouping… f $ g x = f (g x), so the expression `a b c` is still a source for ambiguity.

[avgcorrection]

`$` is an operator. There is no ambiguity (you might not know the precedence table but that doesn’t make it ambigious).

[pklausler]

`$` = id