Y
Hacker News
new
|
ask
|
show
|
jobs
by
Moodles
1455 days ago
Right, but my question is, why is it the correct value? There's some math theorem which makes it true?
m_2 = c^d_q mod q
= m^(e * d_q) mod q = m because?
1 comments
pbsd
1455 days ago
That's just how RSA works, via Fermat's little theorem: e * d_q mod (q-1) = 1, so m^(e * d_q) mod q = m^1 mod q = m.
link
Moodles
1455 days ago
Got it, thank you!
link