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by mkleczek
1482 days ago
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> Because this statement uses "exists" on the property, it does not rule out the existence of a y which works for most properties P that we'd care about. It only rules out one that works for all properties. Translated: there exists a computational model weaker than TM but strong enough to implement programs we care about. Unfortunately, we don't know such computational model and we know empirically surprisingly many problems require a TM (ie. surprisingly many languages are accidentally Turing complete) |
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It is in fact extremely common to build wholly deterministic machines out of the same parts as our unreliable computers, that are correct by construction. And they may implement a Turing-complete language and still be wholly deterministic, just by limiting the input to what can be proven deterministic in a strictly limited time. Again, this is normally by construction, where the proof is always trivial.
Such a proven-correct system can model literally any space-constrained algorithm.