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by arbitrandomuser
1490 days ago
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I've never given a second thought about what the etymology of "spectral" in spectral decomposition is.
Somewhere in the back of my mind (and I guess many students of physics have the same notion) subconsciously i assumed it originates from eigenvalues of the Hamiltonian determining the atomic spectral lines . But I've never followed up on it and actually looked it up . |
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But the way I see it "spectral decomposition of A" is a way to express A as a sum of orthogonal, rank-1, operators. A = \sum l_i u_i u_i^T. Those l_i are the eigenvalues; u_i are the eigenvectors.
The eigenvectors look a whole lot like the "modes" in a Fourier decomposition. And if you plot (i, l_i), the eigenvalues are a bit like the "spectrum" (the amplitude of each mode).
In fact, the complex exponentials (the modes in the Fourier decomposition) are also eigenvectors of a specific operator (the Laplacian).
Math people are good at finding connections between things.