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tgv
1496 days ago
There are other unary operators (!, ~), although I'm almost sure FORTRAN didn't support those, but 1 - -13 => 1 - 0 - 13 = -12 would fail, wouldn't it?
1 comments
Taniwha
1496 days ago
No, not in Fortran of that era ~ was pretty much missing from most card punch keyboards
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