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by contravariant
1520 days ago
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Yeah the author is conflating low entropy with a low number of microstates, which is consistent with the thermodynamic assumption that maximal entropy means a uniform distribution of microstates, but is confusing. The purest mathematical justification for why low entropy means a low number of microstates probably comes from the fact that (classical) physical systems are a dynamical systems that preserve the measure induced by the standard metric of the phase space. The measure theoretic definition of entropy then implies the entropy of a partition of the phase space (i.e. a set of macrostates) is indeed the average of the logarithm of the number of microstates. So indeed if W is the number of microstates in the current macrostate then entropy = log(W) (on average). And using the typical set you can show that the probability that the average of log(W) over n samples is within 'epsilon' of the 'exact' entropy goes to 1 as n goes to infinity. This is the mathematical justification for the second law of thermodynamics. The trick is that all of this is true no matter how you partition phase-space. Though that does mean that what is and isn't a high entropy state depends on your perspective. |
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That seems to be correct.
>Yeah the author is conflating low entropy with a low number of microstates
Since entropy is found by counting micro-states (for example your third paragraph), that should be ok. What am I missing?