[uxp]

Yes. Here's a non-crypto instance of using a seed value to deterministically identify the output of a random number generator. This only works in Python 2.x:

    import random
    for i in range(0,50):
        if not i % 15:
            random.seed(1178741599)
        print [i+1, "Fizz", "Buzz", "FizzBuzz"][random.randint(0,3)]

By seeding the PRNG with a known value, one can literally predict the output of a weak number generation utility. In this case, it solves the FizzBuzz puzzle.

https://en.wikipedia.org/wiki/Fizz_buzz