|
|
|
|
|
by grayclhn
1546 days ago
|
|
To be super pedantic, for one million ops it's closer to a 63% chance every day: Pr[something happens across 1_000_000 events] = 1 - Pr[nothing happens across 1_000_000 events] = 1 - Pr[nothing happens once]^1_000_000 ## assuming independence = 1 - (1 - Pr[something happens once])^1_000_000 = 1 - (1 - 1/1_000_000)^1_000_000 ≈ 1 - 0.378 = 0.632 It's still below 99% for 4 million ops. |
|
Okay, but they said millions.
> It's still below 99% for 4 million ops.
I find this misleading, because it's... 98%.
Which completely undermines your argument. If something happens 98% of days, it's fine to call that "every day".