| The base case is not n=2, it’s clearly stated as n=1 in the proof. The inductive step works fine if you introduce the premise n>=2. It is not valid to introduce that premise. The inductive step is therefore wrong. The proof in the post is saying the base case is P(1) and the inductive case is that for all n, P(n) => P(n+1) “P(1)” is true.
“For all n, P(n) => P(n+1)” is false.
The inductive step is wrong A completely different proof not present in this post could be: Base case: P(1) and P(2)
Inductive case: for all n > 1, P(n) => P(n+1) In that completely different proof, the inductive step would be correct and the base case would be wrong. That proof is not in the original post. |
I would like to give the student partial credit for the "works for n>1" part and deduct points for the missing n=1 case. The two obvious ways to "fix" that are either giving a proof for "P(1)=>P(2)" (which is currently missing) or establishing P(2) another way and then using induction. Both are fixes of the same thing and not at all "completely different".