[cdtwigg]

In this formulation I believe the last bit would also be repeated 3 times, and you’d have to read those three bits to detect corruption.

[dataflow]

Yes but how would you know that without reading all 6 bits first?

[netizen-936824]

You wouldn't, as long as the bits are received sequentially. I think the idea is that, depending on where the corruption is, you only need to read up to two bits past the corrupted one