I think you misunderstood the previous comment. I think that firstly "ls /path" is entered and if the result is ok, then "; rm $_" is added to the copy of the command then executed.
(where "escape" "dot" brings up last argument) without the need to fiddle around with dollar signs underscores, exclamation marks, etc. to prevent further mistakes (e.g. "was it $! or !$ ?", shell expansion, etc)
1. ls /path
2. rm <esc><.>
(where "escape" "dot" brings up last argument) without the need to fiddle around with dollar signs underscores, exclamation marks, etc. to prevent further mistakes (e.g. "was it $! or !$ ?", shell expansion, etc)