Y
Hacker News
new
|
ask
|
show
|
jobs
by
ogogmad
1719 days ago
C([0,1]) is not a Hilbert space but a Banach space. Every Hilbert space is a Banach space, but not vice versa. The version of the theorem for Hilbert spaces is indeed a lot easier to prove than the one given in the article.
1 comments
turminal
1719 days ago
And that just proves my point about confusion :)
Thanks for the correction.
link
Thanks for the correction.