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by ogogmad
1737 days ago
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Computably countable is also a correct term. In line with this approach to computability theory: http://math.andrej.com/asset/data/synthetic-slides.pdf It shows that the unsolvability of the halting problem follows from: - The computable uncountability of N^N, which can be proved using an identical argument to the one Cantor used to prove the set-theoretic uncountability of N^N. - The computable countability of the partial maps from N to N. If the halting problem were solvable, then the second bullet point would contradict the first. So it's essentially a weird twist on set theory that uses constructive logic. |
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However, that's not the point I wanted to make. I wouldn't like calling it computably countable even if everyone else did, simply because it gives the wrong intuition about subsets.