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by vlunkr 1748 days ago
Well, the big one is selecting a parent from the child.
1 comments
androceium 1748 days ago
You could do this with the :has() CSS psuedo-class[0], though inverted (select a parent that _has_ the child matching a selector).

Looks like that psuedo-class has not been implemented in the kuchiki library that htmlq uses though.

[0]: https://developer.mozilla.org/en-US/docs/Web/CSS/:has

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spiralx 1747 days ago
You can do it either way in XPath thanks to how you can use a path expression and/or predicates almost everywhere in a query

  # Find all elements li and select the parent element for each
  //li/.. 

  # Find all element nodes with a child element named li
  //*[li]

  # Non-abbreviated queries
  /descendant::li/parent::*
  /descendant::*[child::li]

  # CSS using :has
  :has(> li)
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