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by _nalply
1747 days ago
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I found about posits. https://www.johndcook.com/blog/2018/04/11/anatomy-of-a-posit... Perhaps CFP8 are parameterized 8-bit posits where the parameter is the value es. The larger es is, the greater the dynamic range is at the expense of precision. Two examples: posit<8, 0> (es = 0) has as largest positive number 64 and the smallest positive number 1/64. posit<8, 1> (es = 1) has as largest positive number 4012 and the smallest positive number 1/4012. The formula for the largest positive number for 8-bit posits is: 2 ^ 2 ^ es ^ 6. posits don't have NaNs and only one infinity (±∞), so they can use more of the 8 bit values for numbers than floating point numbers. I wonder: is CFP8 = posit<8, es>? |
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