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Assuming the 3 hot dog stands start out with spacing to allow for equal coverage, their positions are -2/3, 0, 2/3. Everyone gets 2/3, 1/3rd on each side. The two on the outside have an incentive to move towards 0 because they can take more market share without losing any. The one in the middle does not want to move to either outside area until moving means he can have more market share than what he currently has. If the rightmost player decided to move inward from 2/3 to 0.5, he'd have 0.75 market share (out of 2). The middle player would have 1/3 + 1/4 = 7/12 or 0.58. It still wouldn't be in his interest to become the rightmost player, as his upper market share limit would be 0.5 (a little less). However, there's already an incentive to move to the right player's location, causing the locations to be (-2/3, 0.5, 0.5). The left player gets 1/3 + (2/3 + 0.5)/2 = 1/3 + 1/3 + 1/4 = 11/12 or 0.91. The remainder, 1.09, is split equally among the other two to 0.545 each. Only the left player has incentive to move at this point, since each of the right players stand to lose the right-side market by moving inward, or losing half the left-side market by moving outward. The leftmost player has incentive to move inward now, and can do so until he takes enough market share from the other two that one of them can move to him and gain more. If they all did this and ended up at 0, they'd again have an equal 2/3rds. However, anyone can move slightly to one side or the other and increase his market share to nearly 1. Looks like you're right. I would say there's "equilibrium behavior", though--the 3 players will oscillate between the boundaries [-2/3, 2/3], with someone frequently taking the same position as another. |
This move would not have been made by theoretically optimal players: if he had moved from 2/3 to 0+ instead he would have had 1 market share (out of 2).
> Only the left player has incentive to move at this point, since each of the right players stand to lose the right-side market by moving inward, or losing half the left-side market by moving outward.
The middle player actually has an incentive to move to the center of the board for the same reason that the original player in the two player case had an incentive to choose the middle of the board (despite having monopoly).
> If they all did this and ended up at 0, they'd again have an equal 2/3rds. However, anyone can move slightly to one side or the other and increase his market share to nearly 1.
In this configuration the two players on the outside would actually each have ~1, leaving the player in the middle ~0. If we call these positions using formats like 0-, 0, and 0+, the 0 player will move to 0++, causing either the 0- player to move to 0 and the 0+ player to move to 0--.
Now we have 0--, 0, and 0++. Now, the 0++ player will move to 0+, and the 0 player will move to 0++, leaving the 0-- player to move to 0-. The 0+ player will move to 0--, the 0++ player will move to 0, and the 0- player will move to 0+. "Finally", the 0-- player will move to 0-.
I am pretty certain that this algorithm does not terminate.