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by amw-zero
1781 days ago
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You can turn A->B, B->A into A->I,B->A + A.I=B and that does avoid a circular dependency. A->B means a depends on B, A->I means A depends on an interface, and A.I=B means that B is set as the implementation of the I interface that A depends on. I’m on mobile so that was the best I could come up with. Try it out using Swift though, and that can be translated pretty directly. |
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