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by concreteblock
1793 days ago
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I may have missed this, but doesn't this just raise the question: Why is the fourier transform of position equal to momentum? I.e why is position conjugate to momentum? More generally, why would the fourier transform of an observable be another observable? |
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We can then relate the spatial frequency of a photon to its momentum by the formula p = h * f / c, where h and c are the Planck constant and the speed of light in a vacuum, respectively. From this we see that the momentum of a photon is a function of frequency, which, from the properties of the Fourier transform, we know to be the conjugate pair of position.