|
|
|
|
|
|
by sanctified384
1812 days ago
|
|
|
Two hosts is efficient. Do it twice on two different hosts and then compare the results. If there is a mismatch, throw it away and redo it again on 2 hosts. A total of
4 computations are needed. But only if the difference really was due to bit flips, the chance of which are exceedingly rare.
In all the rest of the cases, you get away with two instead of three computations. |
|
|