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by nly
1846 days ago
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The varint format also isnt as dense on average as it could be and allows for non-canonical encodings. I.e. you can encode any integer in multiple ways (up to 9 or 10 bytes) The solution for this is to subtract 1 from the integer every time you encode a byte (since the existence of the next byte you're adding already indicates that the intermediate value isn't 0) |
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