The probability for executing this strategy is: P(3)+P(5)+P(6)+P(8)+P(9)+P(11)+P(12) * P(4).
Plug in the numbers from https://statweb.stanford.edu/~susan/courses/s60/split/node65...
(0.0556+0.1111+0.1389+0.1389+0.1111+0.0556+0.278)*0.0833 = 0.07407036
So 7.4%.
https://freakonomics.com/2008/12/16/an-all-pay-auction/