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by ben509
1856 days ago
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Yeah, I was pushing that all under "recovery." Say it all sums to $C. Arguably the bigger problem is you don't know that the ransomer will actually give you a valid key, but suppose you guess a likelihood P that they do. Now you have some scenarios: 1. Don't pay. We're out $C. 2. Do pay, and get a valid key. We're out $R. 3. Do pay, and get no key. We're out $R + $C. So the limit is at scenario 1 being equal to the combination of 2 and 3. Set C = PR + (1-P)(R + C), and your max ransom R = CP (You could probably work in additional costs for cleaning up even if the ransom is paid.) |
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