[Fooloo]

How many dyson spheres do we need to account get rid of the dark matter and modified gravity?

[forgotpwd16]

One Dyson sphere of radius 1 AU (Sun-Earth distance) having mass 600 kg/m^2 (8-20 cm thick) will require[1] 10^26 kg of material. The Milky Way's dark mater halo is considered[2] to have mass 10^12 M_Sun = 10^42 kg. So you will need a total of 10^16 (10 quadrillion) spheres.

[1]: https://www.aleph.se/Nada/dysonFAQ.html#ENOUGH

[2]: https://arxiv.org/abs/1306.4013

[paul_f]

What's truly amazing is that all 10 quadrillion spheres are dedicated to cryptocurrency mining.

[samatman]

A common misconception, up to 18% are in fact running Doom.

[Fooloo]

wouldn't you undercount the stars enclosed?

[forgotpwd16]

True. I only considered the spheres (shells) themselves. If you include the star then the result is even simpler. M_Sun is 10^30 kg so for a back of the envelope calculation you don't even have to consider the shell. Therefore you can say 10^12.

[gilbetron]

Dyson spheres would not qualify as dark matter, as they would be made of Baryonic matter.

[Keysh]

Dyson spheres would glow in the mid- and far-infrared (re-radiating energy absorbed from the enclosed star), and so would not be "dark".