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by Dylan16807
1882 days ago
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> This still sounds like precisely what I described. Euler's three-body problem is two fixed point masses, so there's no relative motion by construction, and the restricted three-body problem in a rotating/pulsating reference frame has mathematical transformations applied so the two bodies are "effectively fixed" relative to each other in that reference frame (while preserving effects due to rotations, such as centripetal/centrifugal forces). You still have to care about the where the particle is relative to both masses. The whole point of the calculation is figuring out which way the particle goes, and the simplification I'm suggesting removes a lot of that math. Instead of two masses providing a continuously varying force in both direction and magnitude, you have one mass providing a continuously varying force plus a static offset. This removes multiple degrees of freedom from the problem. > Swapping between the approximation and proper n-body depending on position relative to other bodies seems like a rather complex scheme, though, and I'm not sure whether that'd be the best approach. I wasn't suggesting swapping between the methods. If you're in the middle of nowhere, then while the Keplerian portion of the model will be a smaller factor, it won't harm anything. |
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Ah, so the force vector is constant/infrequently updated, not the position of the second body. My apologies for the misunderstanding.
I'm honestly a bit curious what an that would look like. For example, what would an orbit around the Earth-Moon L1 look like? What would an Earth -> Moon low-energy transfer look like?
I feel like depending on the system you might need to update the "fixed" force vector relatively frequently to get anywhere close to approximating n-body results, which basically sounds like regular integration.
I suppose at some point the question becomes how much fidelity are you willing to sacrifice in the name of decreasing CPU usage.
> I wasn't suggesting swapping between the methods.
My mistake again. Sorry about that.
> If you're in the middle of nowhere, then while the Keplerian portion of the model will be a smaller factor, it won't harm anything.
Wouldn't that arguably be where the most significant errors would be, as that's where the relatively unphysical constant force vector would have the most significant influence?