[prewett]

I don't think I understand how pricing works, but at the most expensive level, it seems to be $15/km^2, so 2 km^2 once a week would be $30/week, right?

[Brajeshwar]

I believe, his calculation is roughly at $30 per week x 4 weeks per month x 12 months a year.

Anyway, the cost of a 3-meter resolution loaded with multispectral bands and metadata will be just about a dollar per sqkm or even less.