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by davidrm 1980 days ago
It’s not a concern, the more powerful the charger, the better.

The devices that are being powered are the ones controlling the charging, the charging brick will derate itself if devices demand more than it can handle. It might hurt the brick, it will get hot or perhaps noisy if it’s a cheaper one.

It’s like openning every single faucet at your house, as long as the pressure and flow at the source are ok, the faucets will output the same as in any other case, otherwise each faucet will “slow down”.

1 comments

Thanks for this. Would that "slowing down" harm the device though? Obviously, I should err on the side of higher wattage, but if the power adapter provides lower wattage than is required, would that harm the device?
No. That really isn’t how electronics works.

Basic charging works on the principle of deciding a charging voltage (which is either 5v or negotiate to be higher via Power Delivery) plus as many amps as the charger can provided.

As a receiving device the only thing you really care about it voltage. If it’s to high, then stuff gets fried, two low and stuff just doesn’t turn on.

The amps are determined by how much the receiving device can consume. And of course decreases as the device charges (if you’ve got a full battery, then you don’t need more power). If the receiving device pulls to many amps, then the voltage will start to drop, this then causes the receiving device to reduce its power consumption.

Ultimately power electronics are extremely robust today, you would have to try very hard to fry modern electronics. This is a result of how modern electronics converts power, which naturally makes them very robust to fluctuating inputs. (I’m simplifying a lot, want to learn more then look up DC-DC converters, and see how they’re implemented in silicon)

In short, just don’t worry.