[MauranKilom]

> In C++ a lambda may not be convertible to a function pointer if the captured context is non zero sized, and if the captured context is larger than the size of a pointer it must use some kind of dynamic allocation

You are mixing things up here. A lambda will never require memory allocation, regardless of its size: https://godbolt.org/z/Mebn4h

std::function can't get around memory allocation for sufficiently large functor objects, but that is a matter of how libraries implement type erasure for functors and has nothing to do with the lambda expressions of the core language.