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by onedognight
5518 days ago
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If you compute the eigenvalue decomposition of A={{0,1},{1,1}}
i.e. A = V^-1 D V
where D is a diagonal matrix with the eigenvalues phi and 1/phi as the diagonals, then A^n = V^-1 D^n V
where D^n is diagonal with phi^n and 1/phi^n as the diagonals. This gives exactly the above well known formula. |
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