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by ezy 5520 days ago
Likewise for auto_ptr<T>, but he glosses over that.
1 comments
shasta 5520 days ago
How do you figure? There isn't an implicit conversion from auto_ptr<T> to T *.
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obiterdictum 5520 days ago
There isn't. There are two explicit methods to get raw pointer value with different semantics:

- get(): auto_ptr retains the ownership

- release(): auto_ptr loses the ownership

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