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by edna314 2064 days ago
Naive question: these images are made at low but finite temperatures, so each atom would fluctuate within its position such that there should be an uncertainty. Is that uncertainty lower than 1 angstrom? Otherwise, how can one talk about atomic resolution if fluctuations are larger?
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The uncertainty also comes from averaging many images together. But yes, it's less than 1 Angstrom; the deposited structures (for example https://www.rcsb.org/structure/7A6A) record atomic uncertainties, "B-factors" or "temperature factors" in crystallographer-speak. In the example I pulled out the B-factors are in the low-double digits for the main-chain atoms, and if I'm remembering the math correctly, this will correspond to atomic displacements with a radius around 0.5 Angstrom. (Of course that's just an estimate by the software that performed the model optimization, but my understanding is that this part is relatively straightforward.)
Hmm, but then the b-factor (and therefore also resolution) is dependent on the flexibility of molecule you want to look at? Does that mean that these guys just found a system for which the main chain was rigid enough such that the thermal fluctuations are low enough?
Oh absolutely, they picked a model system that is both very rigid and has extremely high internal symmetry, and I assume they did rotational averaging to use fewer images. But these ideal systems are very useful for determining the limitations of the underlying technology like electron detectors; 15 years ago the best you could do with a molecule like this was around 4 Angstrom resolution.
Ok, that’s fair. But, then the number makes more sense in relative terms than in absolute. Still, absolutely impressive.