[nercht12]

x = foo()

bar(x.a: x.b:)

Functions can return data. So say, a=5, then to get the value of 5 out, all you have to do is call the function a.

Edit: I'm assuming foo() here returns an object with members "a" and "b". An example of such a function-object would be:

foo = [] { ret( [a=5, b=10] ) }

[uryga]

right, but doesn't that contradict this:

> "in Copper, variables only store functions"

because here, `x` clearly stores an object... is this about the whole "object-function" thing where Copper doesn't really distinguish the two?

(btw i'm sure this is explained in the docs... but maybe this'll help folks like me who often just read the comments)

[nercht12]

Copper does not distinguish between function and object. An object-function has two parts: the member part and the executable body. In C++, it's analogous to:

class FunctionObject {

FunctionObject* members[];

void* operator() { /* executable body */ }

};